(10x^2-18x-24=0)^2

Solution for (10x^2-18x-24=0)^2 equation:

(10x^2-18x-24=0)^2

We move all terms to the left:

(10x^2-18x-24-(0)^2)=0

We get rid of parentheses

10x^2-18x-24-0^2=0

We add all the numbers together, and all the variables

10x^2-18x-24=0

a = 10; b = -18; c = -24;
Δ = b2-4ac
Δ = -182-4·10·(-24)
Δ = 1284
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1284}=\sqrt{4*321}=\sqrt{4}*\sqrt{321}=2\sqrt{321}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{321}}{2*10}=\frac{18-2\sqrt{321}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{321}}{2*10}=\frac{18+2\sqrt{321}}{20}
$